(3^-2 × 4^-2)^-3 = 12^x
In the given expression find the value of x.

Given that (3^-2×4^-2)^-3 = 12^x

⇛ [(3×4)^-2]^-3 = 12^x

Since a^m × b^m = (ab)^m

⇛(12^-2)^-3 = 12^x

⇛ 12^(-2×-3) = 12^x

Since (a^m)^n = a^mn

⇛ 12^6= 12^x

⇛6 = x

Since the bases are equal then exponents must be equal

Therefore,x = 6

Additional comment:-

If the bases are equal then exponents must be equal.

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