rvkanneh1713
30.03.2021 •
Mathematics
3 5 of the first group are right-handed. 80% of the second group are right-handed. What fraction of the class is right-handed?
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Ответ:
Ответ:
7/10
Step-by-step explanation:
To make things simple, let's turn 80% into a fraction, 8/10. To get a common denominator let's turn 8/10 into 4/5. Since they are both of equal size, the first group would have 2/5 left-handed people and the second 1/5 left-handed people. Let's imagine that each group has 5 people in it. There would be 10 people in total. There is 1 person for each fifth so we can add now. 4 + 3 = 7 right handed people. To check, 2 + 1 = 3 and 3 + 7 = 10. so 7/10 of the class is right-handed.
Ответ:
First notice that by reversing the signs of the coefficients of the terms with odd degree, the sum is zero. So
x
=
−
1
is a zero:
f
(
−
1
)
=
1
+
1
+
7
+
9
−
18
=
0
and
(
x
+
1
)
is a factor:
x
4
−
x
3
+
7
x
2
−
9
x
−
18
=
(
x
+
1
)
(
x
3
−
2
x
2
+
9
x
−
18
)
then factor by grouping...
=
(
x
+
1
)
(
(
x
3
−
2
x
2
)
+
(
9
x
−
18
)
)
=
(
x
+
1
)
(
x
2
(
x
−
2
)
+
9
(
x
−
2
)
)
=
(
x
+
1
)
(
x
2
+
9
)
(
x
−
2
)
then take square root of
−
9
to find:
=
(
x
+
1
)
(
x
−
3
i
)
(
x
+
3
i
)
(
x
−
2
)
So the zeros are
x
=
−
1
,
x
=
3
i
,
x
=
−
3
i
and
x
=
2
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