3. what is the value of y^-5/x^-3 for x= 2 and y= -4? a) 10/3 b) 128 c) -1/128 d) -128

Y^-5/x^-3 = x^3/y^5 = (2)^3/(-4)^5 = 8/-1024 = -1/128

There are 8 numbers for the computer to choose from.
So the probability of choosing a particular number is 1/8.
The first number can be any one of the 8.
The second and the third must be the same as the first, with probability 1/8.

Therefore the probability that all three numbers are the same
= (1/8)(1/8) = 1/64   [ player will win a prize ] 
(=0.03125)