Scrublord
25.03.2020 •
Mathematics
37. Which is an equation for the circle with a center
at (-2, 3) and a radius of 3?
A. x2 + y2 + 4x –6y+22=0
B. 2x2 + 2y2 + 3x – 3y+4=0
C. x2 + y2 + 4x -6y+4=0
D. 3x2 + 3y2 + 4x -6y+4=0
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Ответ:
C
Step-by-step explanation:
(x+2)² + (y-3)² = 3²
x² + y² + 4x - 6y + 4 + 9 - 9 = 0
x² + y² + 4x - 6y + 4 = 0
Ответ:
no sign
Step-by-step explanation:
a is 0, b is negative
0×a=0
No sign