3x^{2}-21x-54 what are the zeros? (solutions)

The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=

x^2+7x+18
a=1
b=7
c=18

x=
x=
x=
i=√-1
x=

the zerose would be
x= or

1

Step-by-step explanation:

Given:

Geraldo current age = 25years.

Policy being considered for = 30years

Age at the end of the policy = 55years

What is the probability that Geraldo lives to be 55years.

Therefore

P ( A + B ) = 25 /55 + 30 / 55

= 5 / 11 + 6 / 11

= 11 / 11

= 1