3x - 2(x - 1) = a
Jordan thinks that when a = 2. the equation has infinitely many solutions.
is Jordan correct?

Not infinitely many solutions

Step-by-step explanation:

Let’s substitute 2 in place of “a” and see where that takes us

3x-2x+2=2

X+2=2

X=0

Let’s substitute x as 0 and a as 2 and see what happens then

3(0)2(0)+2=2

2=2

This is a true statement hence the equation is NOT infinitely many solutions as it has only one solution of 0

Hope this helps

By drawing a diagonal in a square you are dividing the square into two congruent isosceles right triangles. Using Pythagorean Theorem we can find the length of the diagonal.

a squared + b squared = c squared
a and b represent the sides of the triangle (aka the length of a side of the square), and c represents the hypotenuse (aka the diagonal).
9 squared + 9 squared = c squared
81 + 81 = c squared
162 = c squared
take the square root of both sides
81= x