(3x^3-2x^2+x-4) /(x-2)

In this you’re just finding the values of the function for the given x values.

f(0) is the y value when x=0, so you look at the graph at x=0 and look at what y value is at the point. At x=0 you get y=1, so f(0)=1.

Same thing with the other function. g(-8)= -6.

Then you substitute those values.

-8(1) + 4(-6) = -8-24 = -32