3x² - 4x – 8=0
does anyone know how to solve this?

That is a quadratic equation.

It can be solved by using the quadratic formula:

x = (-b +-sqr root b^2 -4*a*c) / 2 *a

In this equation a = -3

b = -4 and c = -8

x = (--4 +- sqr root (-4^2 - 4 * -3 * -8)) / (2 * -3)

x = (4 +- sqr root (16 -96)) / -6

x = 4 +- sqr root (-80) / -6

x1 = (4 +8.94427191 * i)  / -6

x2 =(4 -8.94427191 * i)  / -6

Remember that "i" is the square root of minus 1.

Step-by-step explanation:

No becasue -5 is more than positive 0

Step-by-step explanation:

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Hope this helps!!

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