4(80+n)=(3k)nspace, 4, left parenthesis, 80, plus, n, right parenthesis, equals, left parenthesis, 3, k, right parenthesis, n in the equation above, kkk is a constant. for what value of kkk are there no solutions to the equation?

We need to find the value of k at which the equation 4(80+n)=(3k)n has no solution.
Let's solve the above equation for n. So,

By using the distributing property.

Subtract 4n from each sides.

Take out n as a common factor
Divide each sides by 3k-4.

So,
Denominator of a rational equation cannot be 0 because if it will be 0 then the equation will be undefined and there will be no solution.
Here the denominator is 3k-4. Let's set up 3k-4=0 to get the answer. So,





So,
So, for there will be no solution.

0.13

Step-by-step explanation:

First let's find the probability of finding the first species or the second species:

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.61 + 0.08 - 0.28

P(A or B) = 0.41

Then, to find the probability of finding one or another but not both, we just need the symmetric difference of the events, that is: P(A or B) - P(A and B):

P(A or B) - P(A and B) = 0.41 - 0.28 = 0.13