Mathematics: 4x^2 - 6x + 2 = 0a. find the value of the discriminateb. find the exact solutions by using the quadratic formula. show steps.

The answer to ur question is c on e2020...

4x^2 - 6x + 2 = 0a. find the value of the discriminateb.

lil3114

09.01.2022

a. Discriminant = 4

b. x = 1 and $x = \frac{1}{2}$

Step-by-step explanation:

The Sridhar Acharya Formula gives if ax² + bx + c = 0, the then the roots of the equation is given by

$x = \frac{-b +\sqrt{b^{2}-4ac } }{2a}$ and $x = \frac{-b -\sqrt{b^{2}-4ac } }{2a}$

In this solution the term $(b^{2} -4ac)$ is called the discriminant of the original quadratic equation.

Now, in our case the equation is 4x² - 6x + 2 = 0

a. Therefore, the discriminant of this equation is = (-6)² - 4 × 4 × 2 = 4

b. The solutions of the equation are

$x= \frac{-(-6) +\sqrt{4} }{2 \times 4}=1$

and $x= \frac{-(-6) -\sqrt{4} }{2 \times 4}=\frac{1}{2}$ (Answer)

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