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Savtheartist23
12.11.2020 •
Mathematics
5.)
A ball is thrown into the air with an initial velocity of 96 feet per second. Given the formula below wheret,
represents time in seconds and s(t), the height of the ball, when will the ball hit the ground?
s(t) = -16t? + 960
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Ответ:
The time required to hit the ground is required.
The time taken by the ball to reach the ground is 2.45 seconds.
The equation is
At the ground![t=0](/tpl/images/0890/4583/cadf6.png)
so,
The time taken by the ball to reach the ground is 2.45 seconds.
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Ответ:
The ball will hit the ground 6 seconds after it has ben thrown, at t = 6s.
Step-by-step explanation:
The equation for the height of the ball should be:
s(t) = (-16ft/s^2)*t^2 + 96ft/s*t
When s(t) = 0ft, means that the ball is in the ground
This represents the height of the ball as a function of t, the time in seconds.
We can see that at t = 0s:
s(0s) = (-16ft/s^2)*(0s)^2 + 96ft/s*(0s) = 0ft
Then at the time 0 seconds, the ball is in the ground, so we must look at the other root of the equation
(-16ft/s^2)*t^2 + 96ft/s*t = 0ft
To find it, we can use the Bhaskara equation, in this case is:
Then we have the two solutions:
t = (-96ft/s + 96ft/s)/(-32 ft/s^2) = 0s (the one that we already found)
And the other one is:
t = (-96ft/s - 96ft/s)/(-32ft/s^2) = 6s
Then:
s(6s) = 0ft
This means that the ball will hit the ground at t = 6 seconds.
Ответ:
the correct answer is C
Step-by-step explanation: