5. A ladder 17 m long reaches the window of a building 15 m above the ground. Find the distance of the foot of the ladder from the
building
Hint. Let AB be the ladder, CB be the building and B be the
window.
15 m
Then, AB = 17 cm, BC = 15 m, find AC.)
​

8 m.

Step-by-step explanation:

Use the Pythagoras theorem

17^2 = 15^2 + AC^2

AC^2 = (17-15)(17+15) = 2 * 32

AC^2 = 64

AC = 8 m.

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