SAMANTHA1982
19.07.2020 •
Mathematics
5.b) If z^(1/2)=x^(1/2)+y^(1/2) , show that (x+y-z)^2=4xy
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Ответ:
Step-by-step explanation:
(x+y-z)²= 4xy (x+y-z)²- 4xy = 0(x+y-z)²-(2√x√y)² = 0(x+y-z-2√x√y)(x+y-z+2√x√y) =0[(√x-√y)²-z]*[(√x+√y)²-z]=0(√x-√y)²-z = 0 or (√x+√y)²-z = 0We have : z^(1/2)= x^(1/2)+y^(1/2) ⇒ √z = √x + √y ⇒ z = (√x + √y)²
so (√x+√y)²-z = 0so (x+y-z)²= 4xy
Ответ:
this is for homework. not dating.
Step-by-step explanation: