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jenkuehn9220
28.05.2021 •
Mathematics
5) In the figure, triangle ABC is a right triangle at B. If CD = 15, find BC to the nearest tenth.
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Ответ:
BC ≈ 4.0
Step-by-step explanation:
∠ DCA = 180° - 70° = 110° ( adjacent angles )
∠ DAC = 180° - (30 + 110)° ← sum of angles in triangle
∠ DAC = 180° - 140° = 40°
Using the Sine rule in Δ ACD to find common side AC
AC × sin40° = 15 × sin30° ( divide both sides by sin40° )
AC =
≈ 11.668
Using the cosine ratio in right triangle ABC
cos70° =
=
=
( multiply both sides by 11.668 )
11.668 × cos70° = BC , then
BC ≈ 4.0 ( to the nearest tenth )
Ответ:
exponetional way