6^2-8-2*2/2^2=35
where do you put the parenthesis?

  6^2 -(8 -2*2)/2^2 = 35

Step-by-step explanation:

  6^2 -(8 -2*2)/2^2 = 35

This evaluates as ...

  = 36 -(8 -4)/4

  = 36 -(4/4)

  = 36 -1 = 35

2 cm/s

Step-by-step explanation:

y=√{1+x³}

x and y are dependent on t and so;

y(t) =√{1+x(t)³}

Thus;

dy/dx = y'(t) = [3x(t)²•x'(t)]/(2√{1+x(t)³})

We know that;

y=√{1+x³}

Thus;

y'(t) = [3x(t)²•x'(t)]/2y

We are given y' (t) at this instant t(o), thus; y '(t(o)) = 4

and also at that very same t(o);

x(t(o)) = 2 and y(t(o)) = 3

Thus;

Using, y'(t) = [3x(t)²•x'(t)]/2y, we obtain;

4 = [3 x 2² • x'(t)]/2 x 3

4 x 2 x 3 = 12(x'(t))

24 = 12 (x'(t))

(x'(t)) = 24/12 = 2 cm/s