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lucky1940
11.09.2019 •
Mathematics
6.) a kennel owner has 168 feet of fencing with which
to enclose a rectangular region. he wants to subdivide
this region into three smaller rectangles of equal
length. if the total area to be enclosed 832 ft-, what are
the possible dimensions of the region?
Solved
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Ответ:
The possible dimensions of the region are
52 ft by 16 ft
32 ft by 26 ft
Step-by-step explanation:
Let
x -----> the length of the rectangular region
y ----> the width of the rectangular region
we know that
The perimeter of a rectangle is equal to
Remember that
A kennel owner wants to subdivide this region into three smaller rectangles of equal length
so
we also have to take into account the divisions
we have
simplify
The total area to be enclosed is 832 ft^2
The area is equal to
so
substitute equation A in equation B
Solve the quadratic equation by graphing
The solution are y1=16 ft, y2=26 ft
see the attached figure
For
For
therefore
The possible dimensions of the region are
52 ft by 16 ft
32 ft by 26 ft
Ответ: