6) The sum of three consecutive numbers is 120.
What is the smallest of the three numbers ?

39

Step-by-step explanation:

Let the smallest number be n,

then the three numbers are n, n+1 and n+2

Therefore, n+(n+1)+(n+2)=120

Collecting like terms,

n+n+n=120-1-2

3n=117

n=117/3

n=39

Therefore the numbers are 39,40 and 41.

And the smallest number is 39.

No he is not correct.

Step-by-step explanation:

Both points lie at point -8.  Knowing this, we also know that to find the answer we would subtract the two coordinates not add them.  We do this because they lie in the same quadrant.  Therefore, | 12 | - | - 3.5 | = 8.5 units apart.