68% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at least six, and (c) less than four. Im asking to find a,b,c

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jasmine2555

30.03.2020

Mathematics

Balance of the loan at the end of 2 months = $252357.32

Step-by-step explanation:

Principal = $25000

Interest = 6.2% , Monthly Payment = 231.49

n = number of times the interest is compounded in a year

⇒ n = 1 ( because it is mentioned the rate is compounded is monthly )

Time = 1 month = 0.083 years

Balance of the loan at the end of one month :

$Amount=P\cdot (1+\frac{rate}{n})^{n\cdot t}\\\\Amount=25000\cdot (1+\frac{6.2}{100\times 12})^{12\times \frac{1}{12}}\\\\\implies Amount =\$251291.67$

Balance of the loan at the end of two months :

Now after monthly payment of $239.31, the Principal becomes :

Principal = Amount after one month - Monthly Payment

= 251291.67 - 231.49

= $ 251060.18

$Amount=P\cdot (1+\frac{rate}{n})^{n\cdot t}\\\\Amount=251060.18\cdot (1+\frac{6.2}{100\times 12})^{12\times \frac{1}{12}}\\\\\implies Amount =\$252357.32$

Hence , Balance of the loan at the end of 2 months = $252357.32

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68% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is ​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four. Im asking to find a,b,c