brinks7994

28.11.2021 •

Mathematics

(-7/10 + 0.15) ➗ (-0.125)
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Ответ:

natalie2sheffield

27.04.2020

Mathematics

(b) It is symmetrical about x = 1

Step-by-step explanation:

Given

y = 2(x - 1)^2 - 5

See attachment for options

Required

True statement about the graph

First, we check the line of symmetric

y = 2(x - 1)^2 - 5

Expand

y = 2(x^2 - 2x + 1) - 5

Open bracket

y = 2x^2 - 4x + 2 - 5

y = 2x^2 - 4x -3

A quadratic equation y = ax^2 + bx + c has the following line of symmetry

$x = -\frac{b}{2a}$

By comparison, the equation becomes:

$x = -\frac{-4}{2*2}$

$x = \frac{4}{4}$

x = 1

Hence, the line of symmetry is at: x = 1

(b) is true.

The equation y=2(x-1)^2-5y=2(x−1)

2
−5y, equals, 2, left parenthesis, x, minus, 1, right parenthesi

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(-7/10 + 0.15) ➗ (-0.125) Plz show step by step