7-107. identify the terms, coefficients, constant terms, and factors in each expression below.
a. 3x2 + (−4x) + 1
b. 3(2x − 1) + 2

A. The terms are: (1) 3x² , (2) -4x and, (3) 1
     coefficients: (1)   3  and (2) - 4
     constant term: 1
  
b. 3(2x - 1) + 2
    This can be simplified into: 6x - 3 + 2 = 6x - 1
     terms are: 6x and -1
     coefficients: 6
     constant term: -1

a. Terms:

Coefficients: 3, -4

Constant terms: 1

Factors: (3x -1) and (x -1)

b. Terms: 6x, -1

Coefficients: 6

Constant terms: -1

Factors: No factors

Step-by-step explanation:

The given expressions are:

a.

b. 3(2x -1) + 2

Let's take the first expression

can be written as because +(-4x) = -4x

Terms:

Coefficients: 3, -4

Constant terms: 1

Factors:

=

So, the factors are (3x -1) and (x -1)

Let's take second expression.

3(2x -1) + 2

Let's simplify this. Using the distributive property a(b -c) = ab - ac

3(2x -1) + 2  = 3(2x) +3(-1) + 2

= 6x - 3 + 2

= 6x -1

Terms: 6x, -1

Coefficients: 6

Constant terms: -1

Factors:

No factors

These are the answers!!

Write 2x – 5 over 1.  Factor numerators and denominators, when possible . Divide out common factors to simplify.  Determine that the volume is (x)(6x)(2x – 5).