courtlyn8
04.11.2019 •
Mathematics
85.87 j or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°c
to 34.29°c. calculate the specific heat of the substance.
Solved
Show answers
More tips
- H Health and Medicine How to Increase Blood Pressure without Medication?...
- F Food and Cooking What to Give as a Wedding Gift?...
- F Food and Cooking Everything You Need to Know About Pasta...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
- S Style and Beauty How to Make Your Lips Fuller? Ideas and Tips for Beautiful Lips...
- C Computers and Internet How to Learn to Type Fast?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
Answers on questions: Mathematics
- M Mathematics Find the slope of the line passes through (10, 8) and (1, 1) Please help?...
- M Mathematics Which of the following are polynomials?...
- M Mathematics The amount of water in a pool varies directly with the amount of time it is filling up. The pool has 2,900 liters of water after 15 seconds. How many liters of water will the pool...
- M Mathematics 3. Find the measure of each angle to the nearest tenth of a degree. a) sin A=0.2345 b) cos B=0.8765 c) tan C= 1.2345...
- M Mathematics Evaluate 2x+6y when x= -4/5 and y= 1/3 Write your answer as a fraction or mixed number in simplest form....
- M Mathematics Point T is on line segment SU. Given TU = I - - 1, SU = 33 - 7, and ST = 2 + 7, determine the numerical length of TU. TU Submit Answer attempt 1 out of 5 problem 1 out of max 1...
- M Mathematics Why does.math need.to be so hard....
- M Mathematics (-12x^8 – 2v) - 11x^8...
- M Mathematics Emiko.makes shibori scarves and sells them for $48 each on a website for handmade goods ....
- M Mathematics The dimensions of a rectangular garden are: Length (2x + 3) and the width is (3x-5) Find the value of x if the perimeter is equal to 26....
Ответ:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S =
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Ответ:
the answer is -31/20
Step-by-step explanation: