Mathematics: (8w^1+4x^1)(5w^1-6x^1) *multiplying polynomials*

Your answer would be 6 times 8 = 48...

(8w^1+4x^1)(5w^1-6x^1) *multiplying polynomials* - id81415161183749, stonerofmisery676

Ответ:

J3ak06

10.03.2022

Mathematics

$40w^{2}-28wx-24x^{2}$

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

- First, you must apply the Distributive property. According the exponents properties (product of powers property), if you multiply powers with the same base, you must add the exponents. Then, you have:

$(8w^{1})(5w^{1})+(8w^{1})(-6x^{1})+(4x^{1})(5w^{1})+(4x^{1})(-6x^{1})=40w^{2}-48wx+20wx-24x^{2}$

-Finally, you must add like terms. Then, you obtain the following result:

$40w^{2}-28wx-24x^{2}$

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(8w^1+4x^1)(5w^1-6x^1) multiplying polynomials

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