9(6k + 3r)=

A) 15k+12r

B) 54k+27r

C) 6(3k+0r

D) 3(18k+9r​

B

Step-by-step explanation:

9*6k+9*3r

54k+27r so the answer is B

16 km due west

Step-by-step explanation:

The bearing of the school p from school q is 16 km due west.

To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.

Since p is directly west of q, then it implies that q must be directly east of p.

We now know the direction.

Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.

Hence, the bearing of q from p is 16 km due west.