A 14 gram sample of a substance that's used to preserve fruit and vegetables has
a k-value of 0.1095.
-kt
N = Noe
No = initial mass (at time t = 0)
N = mass at time t
k = a positive constant that depends on
the substance itself and on the units
used to measure time
t = time, in days

Find half-life in days. Round to nearest tenth

The half-life in days is 6.3 days

Step-by-step explanation:

Here, we want to get the half-life

From what we have in the question, we can see that we have a first order decay relation

For a first order decay relation;

t1/2 = ln 2/k

That will be;

t1/2 = ln2/0.1095

t1/2 = 6.33

To the nearest tenth, this is 6.3 days

confidence interval = ( -0.38 , 0.08 )

Step-by-step explanation:

Given data :

n1 = 55 , n2 = 60 ,

Let P1 ( proportion of SUV sales at store A ) = 30 / 55 = 0.55

P2 ( sample proportion of SUV sales at store B ) = 42/60 = 0.70

The Z-value at 99% confidence Interval = 2.58

Determine the 99% confidence interval for difference in proportion

applying the formula below

( P1 - P2 ) ± Z (

Input values above into equation

confidence interval = ( -0.38 , 0.08 )