Mathematics: A(-2,3) b(3,0) c (-4,-3) what is the perimeter of the triangle? round to the nearest tenth.

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A(-2,3) b(3,0) c (-4,-3) what is the perimeter - id2330434107169, stichgotrich849

Ответ:

villarrealc1987

12.01.2022

Mathematics

The perimeter of triangle is 19.8 units

Step-by-step explanation:

we know that

The perimeter of triangle ABC is

P=AB+BC+AC

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

we have

A(-2,3),B(3,0)

substitute in the formula

$d=\sqrt{(0-3)^{2}+(3+2)^{2}}$

$d=\sqrt{(-3)^{2}+(5)^{2}}$

$d_A_B=\sqrt{34}\ units$

step 2

Find the distance BC

we have

B(3,0),C (-4,-3)

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(-4-3)^{2}}$

$d=\sqrt{(-3)^{2}+(-7)^{2}}$

$d_B_C=\sqrt{58}\ units$

step 3

Find the distance AC

we have

A(-2,3),C (-4,-3)

substitute in the formula

$d=\sqrt{(-3-3)^{2}+(-4+2)^{2}}$

$d=\sqrt{(-6)^{2}+(-2)^{2}}$

$d_A_C=\sqrt{40}\ units$

step 4

Find the perimeter

P=AB+BC+AC

substitute the values

$P=\sqrt{34}+\sqrt{58}+\sqrt{40}$

$P=19.8\ units$

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A(-2,3)
b(3,0)
c (-4,-3)
what is the perimeter of the triangle? round to the nearest tenth.

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