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ICyberAngel
15.07.2020 •
Mathematics
A 20-kilogram mass is attached to a spring. If the frequency of simple harmonic motion is 2/p cycles/s, what is the spring constant k? What is the frequency of simple harmonic motion if the original mass is replaced with an 80-kilogram mass?
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Ответ:
Step-by-step explanation:
Frequency of a mass-spring system is:
f = √(k/m) / (2π)
Given f = 2/π Hz and m = 20 kg:
2/π Hz = √(k / 20 kg) / (2π)
4 Hz = √(k / 20 kg)
16 s⁻² = k / 20 kg
k = 320 kg/s²
k = 320 N/m
If the 20 kg mass is replaced with an 80 kg mass, the frequency is:
f = √(320 kg/s² / 80 kg) / (2π)
f = √(4 s⁻²) / (2π)
f = 2 Hz / (2π)
f = 1/π Hz
Ответ:
you would have to multiply 44 by 15
44 x 15
=660