A bag contains 5 milk and 13 dark chocolates. A sweet is selected at random.
What is the probability of choosing:
P(milk)
=

P(not milk)
=

P(milk) 5/18 - 27% P(not milk) 13/18- 73%

         

Step-by-step explanation:

total chocolates in the bag= 18   (5 milk chocolates + 13 dark chocolates= 18 chocolates in total)

to find percentages divide numerator by denominator ( 5/18 = 27%) (13/18=73%)

P(milk) - 27% chance you will get milk chocolate

P(not milk) 73% chance you will get dark chocolate

It is more likey to get dark chocolate

First of all Horner
First we try with -3
1. 2. -5. -6.
-3. 3. 6
1. -1. -2. 0
To verify: -3^3+2*-3^2+15-6=0

Now we have this equation
(X+3)*(x^2 - x -2)=0

I dont know If you know sum and product but that is the easiest way so sum= 1 product = 2 so 2 and -1 are the answers.
You can do this too by this way : b^2-4ac= D
X= (-b(+or-)d^1/2)/2a

So all the zeros
2, -1 and -3
If you want more explanation, send me a comment x