A bag contains 666 red balls, 444 green balls, and 333 blue balls. If we choose a ball, then another ball without putting the first one back in the bag, what is the probability that the first ball will be green and the second will be red?

Step-by-step explanation:

Number Of Red Balls=6

Number Of Green Balls=4

Number Of blue Balls=3

Total Number Of Balls=6+4+3=13

Notice that the two balls are picked without replacement. In this case, the total number of balls always decreases.

P(first ball will be green and the second will be red)

(2-1)3 with 7

I think it's that answer sorry if I get it wrong