A bag of coins contains only quarters and dimes. • The number of dimes in the bag can be represented by x.
• The number of quarters is 6 more than twice the number of dimes.
• There are a total of 276 coins in the bag.
What is x, the number of dimes in the bag?

helpp pls

Number of dimes in the bag = 90

Number of quarters in the bag = 186

Step-by-step explanation:

Let

x = Number of dimes in the bag

y = Number of quarters in the bag

= 2x + 6

Total = 276

276 = x + 2x + 6

276 = 3x + 6

276 - 6 = 3x

270 = 3x

x = 270/3

= 90

x = 90

Number of dimes in the bag = 90

Number of quarters in the bag = 2x + 6

= 2(90) + 6

=180 + 6

= 186

Total = Number of dimes in the bag + Number of quarters

= 90 + 186

= 276

10u3 + 4u2 - 2u + 10

Step-by-step explanation:

( 4u3 + 4u2 + 2) + ( 6u3 - 2u + 8)

opening the bracket

4u3 + 4u2 + 2 + 6u3 - 2u + 8

collecting like terms

4u3 + 6u3 + 4u2 - 2u + 2 + 8

10u3 + 4u2 - 2u + 10