A baseball player throws a baseball from a height of 1 m above the ground and its height is given by the equation h= -3.2^2+ 12.8t +1, where H is the height in meters above the ground, and t, in seconds, is its time in the air [see the image below]. When, to the nearest tenth of a second, will the ball hit the ground? (You must solve by factoring)!!!<<<<< it's important that you do. please solve this ASAP

4.1 sec

Step-by-step explanation:

h(t)=-3.2t^2+12.8t+1

h(t)=-3.2(t^2-4t)+1

h(t)=-3.2(t^2-4t+4-4)+1

h(t)=13.8-3.2(t-2)^2

For the ball to touch ground, h(t)=0.

13.8-3.2(t-2)^2=0

(t-2)=2.0766

t=4.07≈4.1 sec.

There are two ways you could calculate slope.

The first is using two points on the line. Plug the coordinates into the formula:

y₁ - y₂ / x₁ - x₂

This is the difference in rise divided by the difference in run, or rise/run. Our marked coordinates are (-2, -3) and (0, 1).

y₁ - y₂ / x₁ - x₂

-3 - 1 / -2 - 0

-4 / -2

2

The second method is much faster: Look at the graph; count the amount of units the graph rises and the amount of units the graph runs, then divide the former number by the latter number (see attachment).

4 / 2 = 2

Slope = 2