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joynerjaila
02.07.2020 •
Mathematics
A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 54 specimens and counts the number of seeds in each. Use her sample results (mean = 81.1, standard deviation = 8.4) to find the 90% confidence interval for the number of seeds for the species. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places.
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Ответ:
90% confidence interval for the number of seeds for the species
(78.8073 ,83.3927)
Step-by-step explanation:
Step(i):-
Given sample size 'n' =54
Mean of the sample x⁻ = 81.1
standard deviation of the sample 'S' = 8.4
90% confidence interval for the number of seeds for the species
Step(ii):-
Degrees of freedom
ν = n-1 = 54-1 =53
(81.1- 2.2927 ,81.1 + 2.2927 )
(78.8073 ,83.3927)
Final -
90% confidence interval for the number of seeds for the species
(78.8073 ,83.3927)
Ответ: