A boy at an amusement park has 65 ride tickets. Each ride on the roller coaster costs 7 tickets. After riding the roller coaster as many times as he can, how many tickets will the boy have left?

The boy will have 2 tickets left.

Step-by-step explanation:

First you have to figure out how many times 7 goes into 65. As 65 is not a multiple of 7, you have to look for the closest number. In this case, 7*9=63. That is the closest number to 65 that is also a multiple of 7, so the boy can ride the roller coaster 9 times. Since the question is asking how many tickets the boy will have left, you simply subtract 65-63=2. So, the boy will have 2 tickets left.

Hope this helped :)

  105 m

Step-by-step explanation:

  distance/time = (63 m)/(3 s) = d/(5 s)

Multiplying by (5 s) gives the distance d as ...

  d = (5 s)(63 m)/(3 s) = 105 m

An ostrich can run 105 m in 5 seconds.