A car leaves a city at the rate of 60 mi/h and goes 80 miles before a second car follows at a rate of 70 mi/h. In this situation, let x= the number of hours, and y= the distance the car
travels. The distance the first car travels can be represented by the equation y=60x+80.
Part A: Write the equation that represents the distance travelled by the second car.

y = 70x

Step-by-step explanation:

1 solution

Step-by-step explanation:

                                                  1)combine like terms

                                                    2) Subtract variable from

                                                           both sides

                                                   3) subtract numbers on both        

                                                        sides

                                                     4) then divide

3z+9+14z=4z+5

17z+9=4z+5  

-4z    =-4z

13z+9=5

     -9=-9

13z=-4

z= -4/13