A certain large manufacturing facility produces 20,000 parts each week. The manager of the facility estimates that about 1% of the parts they make are defective. What is the variance for the number of defective parts made each week

198 is the variance for the number of defective parts made each week.      

Step-by-step explanation:

We are given the following in the question:

Number of parts produced each week =  20,000

Percentage of defective parts = 1%

We have to calculate the variance for the number of defective parts made each week.

We treat defective part as a success.

P(Defective part) = 1% = 0.01

Then the number defective parts follows a binomial distribution .

Formula for variance =

Thus, 198 is the variance for the number of defective parts made each week.

2 x pi = about 6.3

I think it goes at 6.3

If you can't do that-- I'd round down to 6

hope that helps