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jacksonhoyt8049
06.05.2020 •
Mathematics
A CHICKEN COOP HOLDS A TOTAL OF 10 HENS OR 20 CHICKS. IF 2/5THS OF THE HENS IN A FULL COOP ARE REMOVED, HOW MANY NEW CHICKS COULD FIT IN THE CHICKEN COOP?
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Ответ:
8 new chicks can be fitted in the coop.
Step-by-step explanation:
A chicken coop holds 10 hens or 20 chicks.
That means space in the coop for 10 hens = space for 20 chicks
Or space for 1 hen = space for 2 chicks
Now
th of the hens were removed from the coop.
So, number of hens removed from the coop =![\frac{2}{5}\times 10](/tpl/images/0647/3274/b0147.png)
= 4 hens
And space for 4 hens in the coop = space for the 8 chicks
Therefore, 8 new chicks can be fitted in the coop.
Ответ:
8 new chicks can be fitted in the coop.
Step-by-step explanation:
A chicken coop holds 10 hens or 20 chicks.
That means space in the coop for 10 hens = space for 20 chicks
Or space for 1 hen = space for 2 chicks
Now th of the hens were removed from the coop.
So, number of hens removed from the coop =
= 4 hens. So, 8 eggs.
Step-by-step explanation:
Ответ:
Answer
The independent variable is the number of people. The initial value (initial fee) for the picnic is $40. As the number of people increases, the total cost of the picnic increases.