abebaretosuacegod445
14.02.2020 •
Mathematics
A clock is constructed so that it keeps perfect time when its simple pendulum has a period of 1.000 s at locations where g 5 9.800 m/s2. The pendulum bob has length L 5 0.248 2 m, and instead of keeping perfect time, the clock runs slow by 1.500 minutes per day. (a) What is the free-fall acceleration at the clock’s location? (b) What length of pendulum bob is required for the clock to keep perfect time?
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Ответ:
Answer
Given,
Period of the Pendulum, T= 1 s
acceleration due to gravity, g = 9.8 m/s²
Length of Bob = 0.2482 m
Loss of time in the clock = 1.5 minutes/ day
Loss of time in 1 oscillation
=
= 0.001042
Hence, time period, T = 1 + 0.001042
T = 1.001042 s
a) Using Time period of oscillation formula
Free fall acceleration at the clock location = 9.77 m/s²
b) Length of pendulum bob to keep it perfect time
Hence, Length of pendulum bob is equal to 0.2475 m.
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