A colony of flowers is pollinated by hummingbirds and sunbirds. Let H represents the number of hummingbirds and S represent the number of sunbirds that must pollinate the colony so it can survive until next year.
6H+ 4S> 74
This year, 8How many birds pollinated the colony. What is the least number of sunbirds that must pollinate the colony to ensure that are all survive until next tear?

Complete Question:

A colony of flowers is pollinated by hummingbirds and sunbirds. Let H represents the number of hummingbirds and S represent the number of sunbirds that must pollinate the colony so it can survive until next year.

6H+ 4S> 74

This year, 8 hummingbirds pollinated the colony. What is the least number of sun birds that must pollinate the colony to ensure that it will survive until next year?

The least number of sun birds is 7

Solution:

Given inequality is:

6H + 4S > 74

Where,

H is the number of hummingbirds

S is the number of sunbirds

This year, 8 hummingbirds pollinated the colony

Substitute H = 8 in given inequality

6(8) + 4S > 74

48 + 4S > 74

Subtract 48 from both sides

48 + 4S - 48 > 74 - 48

4S > 26

Divide both sides by 4

S > 6.5

Hence the least number of sun birds is 7

Let the smallest integer be 2n,n∈R . So the next two consecutive integers will be 2n+2 and 2n+4 . So, the smallest number will be 10