A consultant for an association of personnel directors wants to find the proportion of clerical personnel that change jobs because they are bored with their work. The consultant queries a random sample of 400 clerical workers who recently changed jobs, 200 of which state that they changed jobs because they were bored. The consultant wishes to prepare a 95% confidence interval for the true proportion changing jobs because of boredom. What is the margin of error for this interval

the margin of error for this interval is 0.049

Step-by-step explanation:

The computation of the margin of error for this interval is shown below;

Given that

n = 400

x = 200

Now

p = x ÷ n = 200 ÷ 400 = 0.5

Now the margin of error is

=

= 0.049

Hence the margin of error for this interval is 0.049

D

Step-by-step explanation:

10*20=200

200 + 1020= 1220

Works for the first one

20*20=400

400+ 1020=1420

Works for the second one

30*20=600

600+1020=1620

Works for the third one, and all the others one so forth.

You take the number on the left (10, 20, 30, 40, 50, 60, 70) and times it by 20, replacing the x in the equation with the number on the left side of the table. Then you add the number from said equation to result of the multiplication from the first step.