leslymejiaquiroz1
28.06.2020 •
Mathematics
A consumer organization estimates that 35% of the households in a particular community have one television set, 39% have two sets, and 16% have three or more sets. If two independent households are chosen at random, what is the probability that at least one has one or more television sets
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Ответ:
90%
Step-by-step explanation:
Probability of households with one TV = 35% or 0.35
Probability of households with two sets = 39% or 0.39
Probability of households with three or more = 16% or 0.16
The probability of a household with no TV set = 0.10 or 10% (1 - 0.35 - 0.39 - 0.16)
Therefore, the probability of a household with at least one or more sets = 90% (35% + 39% + 16%) or 100% - 10%.
Probability is the chance that something may occur out of many events. To calculate probability, we divide the number of events by the number of possible outcomes.
Ответ:
7
Step-by-step explanation:
sqrt x - (- sqrt x) = 5.3
2 sqrt x = 5.3
Squaring both sides
4x = 5.3^2 = 28.09
x = 7.013
The number is 7