A curve is given by the parametric equations x = cos 2t * a * n * d * y = sin t , then the cartesian equation of the curve is given by: a x = y ^ 2 + 1; y ^ 2 = (1 - x)/2; x ^ 2 + y ^ 2 = 1; x ^ 2 = (1 - y)/2; y ^ 2 = x + 1 d e

Y² = (1-X) / 2

Step-by-step explanation:

According To The Question, We Have

X= Cos2t  &   Y= Sint

the cartesian equation of the curve is given by Y² = (1-X) / 2 .

Proof, Put The Value of X & Y in Cartesian Equation, We get

Sin²t = {1-(1-2×Sin²t)} / 2         [∴ Cos2t = 1 - 2×Sin²t]

Taking R.H.S

(y-2)(3x^2-2)

Step-by-step explanation: