A cylindrical water tank has a height of 20cm and a radius of 14cm. If it is filled to 2/5 of its capacity, calculate. I. Quantity of water in the tank

II. Quantity of water left to fill the tank to its capacity.

Step-by-step explanation:

the volume of a cylinder is simply ground area times height.

the area of a circle is pi×r²

so, in total we have pi×r²×h

r = 14

h = 20

so, the total capacity is

Ct = pi × 14² × 20 = pi × 196 × 20 = pi × 3920 =

= 12315 cm³ = 12315 ml = 12.315 liters

I.

only 2/5 of the total capacity is filled.

so, the filled capacity is

Cf = 12315 × 2 / 5 = 2463 × 2 = 4926 ml = 4.926 liters

II.

it is the remainder to the total.

so, the empty capacity that can still be filled is

Ce = 12315 - 4926 = 7389 ml = 7.389 liters

2+2 = 4 anyone can do that lol

Step-by-step explanation: