A division problem divides a 3-digit number by a 1 digit number. The quotient is 307 r3. What could the division problem be?

There is no solution to this problem.

Step-by-step explanation:

The 1 digit number cannot be 1, since there would be no remainder.

The 1 digit number cannot be 2, since the remainder could be 0 or 1.

The 1 digit number cannot be 3, since the remainder could be 0, 1, or 2.

So, the 1 digit number must be greater than 3.  Let's start with 4.  Since the quotient is 307 (remainder 3), 4 x 307 is already more than 3 digits.

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