A driver brings a car to a full stop in 2.0s. It’s acceleration is -11 m/s^2. How far did the car travel while braking

The answer is -22 meters

The parameters given in the question are;

time(t)= 2.0 seconds

acceleration= - 11m/s²

The formula for distance is

= 1/2at²

= 1/2 × (-11) × (2²)

= 1/2 ×(-11) × 4

= 1/2 × (-44)

= -44/2

= - 22

Hence the distance is -22 meters

Please see the link below for more information

link

  22 m

Step-by-step explanation:

The distance traveled is ...

  d = (1/2)at^2

where "a" is the magnitude of the acceleration.

  d = (1/2)(11 m/s^2)(2 s)^2

  d = 22 m

The car traveled 22 meters while braking.

Solve the two equations simultaneously:
3x+5y=100
x+y=24
Multiply the 2nd equation by 3 so you can have the same coefficient of one of the variables (in this case, x)
3x+5y=100
3x+3y=72
Minus the second equation from the first to give you:
2y=28
Divide by 2 on both sides to give you y=14
Substitute 14 for y into one of the equations:
x+y=24
x=10
Remember that 3x+5y=100
So the test contains 10 3 point questions and 14 5 point questions.