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Tcareyoliver
12.07.2019 •
Mathematics
"a frog is sitting on a stump 12 feet above the ground. it hops off the stump and lands on the ground 6 feet away. during its leap, its height h is given by the equation h equals negative 0.5 x squared plus x plus 12 where x is the distance in feet from the base of the stump, and h is height in feet. how far was the frog from the base of the stump when it was 0.5 feet above the ground? "
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Ответ:
Solution:
Given equation: h = -0.5x² + x + 12
h = 0.5
-0.5x² + x + 12 = 0.5
-0.5x² + x + 11.5 = 0
Find the roots of quadratic equation.
x = ((-b )+- √(b² - 4ac))/2a
= ((-1 )+- √(1² - 4*(-0.5)*(11.5)))/2(1)
= -3.9, 5.9
The distance will not be negative.
Hence, the distance is 5.9.
Ответ: