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alyonaprotopopova
05.01.2021 •
Mathematics
A gardener who wants a rectangular garden whose lot perimeter is 40 meters is suggested by a fellow gardener a plan that would make it so that the build would have a maximum lot area. What could be the suggestion? You must answer in a mathematical solution. Show work.
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Ответ:
a*(20-a)
Step-by-step explanation:
Let's assume that the length of the garden is a the width is b and the area is s.
b = 40/2 - a = 20-a
s =a*(20-a)=-a^2+20a=-(a-10)^2+100
then,
when a=10, max(-(a-10)^2) =0, max(s)=100
Ответ:
Larger:x Smaller:y
x=2y-5
x=-4y+7
x=2y-5=-4y+7