Gerber7778

27.11.2020 • 

Mathematics

A half-life is the time taken for the radioactivity of a specified isotope to fall to half its original value. If an isotope had 40g after 2 half-lives the isotope would be reduced to just 10g. 40\cdot\frac{1}{2}\cdot\frac{1}{2}=1040⋅

2

1



⋅

2

1



=10

Using the function f\left(x\right)=100\cdot\left(\frac{1}{2}\right)^xf(x)=100⋅(

2

1



)

x

where 100 is the original value of the isotope and x is the number of days that have happened.

What is the first day that an isotope with 100g falls below 1g?

Ответ:

narutoxptheninja

09.08.2021

Mathematics

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n = 10

Step-by-step explanation:

=> 2(4 + n) = 28

=> 2(4) + 2(n) = 28

=> 8 + 2n = 28

=> 2n = 28 - 8

=> 2n = 20

=> n = 20/2

=> n = 10

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