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24.03.2020 •
Mathematics
A hot- air balloon is rising from the ground at a rate of 4 feet every second. Another balloon at 756 feet is descending at a rate of 3 feet every second. In how many seconds will the two balloons be at the same altitude.
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Ответ:
108 seconds.
Step-by-step explanation:
Let x represent number of seconds.
We have been given that a hot- air balloon is rising from the ground at a rate of 4 feet every second. So altitude of hot-air balloon would be
feet after x seconds.
We are also told that another balloon at 756 feet is descending at a rate of 3 feet every second. Since the altitude of 2nd balloon is descending, so altitude after x seconds would be initial altitude minus change in altitude after x seconds
.
Now, we will equate both expression to find the time as:
Therefore, the two balloons will be at the same altitude in 108 seconds.
Ответ:
Step-by-step explanation:
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