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caldonjoshhsms2061
09.01.2021 •
Mathematics
A hotdog stand sells hot dogs for 2.75 each and drinks for $1.50 each. Each person in a group of n people bought two hot dogs and one drink. Which equation gives y, the total cost in dollars
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Ответ:
The total cost in dollars, y = $7n.
Step-by-step explanation:
a) Data and Calculations:
Price of hot dogs = $2,75 each
Price of drinks = $1.50 each
Cost of hot dogs bought by one person = 2*2.75 = 5.5
Cost of drinks bought by one person = 1.50
Number of people in a group = n
y = total cost in dollars
y= n($5.5 + 1.50)
y = n * $7
y = $7n
b) Each person's purchase of hot dogs will cost $5.5 (2*2.75). When the cost of hot dogs per person is added to the cost of drinks per person, we have $7 ($5.50 + 1.50). This implies each person will consume hot dogs and drinks worth $7. The total cost will then be $7 multiplied by n, the number of people ($7n).
Ответ:
And the F statistic calculated from the mean squares if
. And for this case we know that
. So then we can reject the null hypothesis that all the means are equal at a significance level given
. And the best conclusion would be:
reject H0 since there is evidence all the means differ.
Step-by-step explanation:
Previous concepts
Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".
The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"
Solution to the problem
The hypothesis for this case are:
Null hypothesis:![\mu_{A}=\mu_{B}=....=\mu_{k}](/tpl/images/0618/3102/d253c.png)
Alternative hypothesis: Not all the means are equal![\mu_{i}\neq \mu_{j}, i,j=A,B,...,k](/tpl/images/0618/3102/77b44.png)
If we assume that we have
groups and on each group from
we have
individuals on each group we can define the following formulas of variation:
And we have this property
And the F statistic calculated from the mean squares if
. And for this case we know that
. So then we can reject the null hypothesis that all the means are equal at a significance level given
. And the best conclusion would be:
reject H0 since there is evidence all the means differ.