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AleOfficial101
30.01.2020 •
Mathematics
(a) how many ordered pairs (x,y) of integers are there such that \sqrt{x^2 + y^2} = 5? does the question have a geometric interpretation?
(b) how many ordered triples (x,y,z) of integers are there such that \sqrt{x^2 + y^2 + z^2} = 7? does the question have a geometric interpretation?
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Ответ:
x, y can take the value of-4, -3, 3, 4
Required ordered pairs are (-4, -3), (-4, 3), (-3, -4), (-3, 4), (3, -4), (3, 4), (4, -3), (4, 3).
Therefore, there are 8 ordered pairs (x, y) of integers.
b.) Given that
x, y, z can take the value of -6, -3, -2, 2, 3, 6
Required ordered pairs are (-6, -3, -2), (-6, -3, 2), (-6, -2, -3), (-6, -2, 3), (-6, 2, -3), (-6, 2, 3), (-6, 3, -2), (-6, 3, 2) . . .
Therefore, there are 8 x 6 = 48 ordered triples (x, y, z) of integers.
Ответ:
boston
Explanation:
because