A line has a slope of - 1/2 and a y intercept of -2 what is the x intercept line?

The x-intercept would be (-4,0).

To find your x-intercept or y-intercept in these cases (specifically the x-intercept) we need to use STANDARD FORM. In this case we can make the slope intercept equation from our given (y=mx+b).

With our given slope and y-intercept we can simply write our equation as y=-1/2x-2. Next we want to find the standard form of this equation (Ax+By=C) when doing standard form we can only have INTEGERS in which case we cannot have fractions of decimals.

Now to set this up we want to have both the x and y values on the LEFT side of the equation. To move -1/2x from y=-1/2x-2 we need to add both sides by 1/2 in which case we get the new equation 1/2x+y=-2. Now we need to get rid of the 1/2 because it is not an integer. An easy way to get fractions to whole numbers is multiplying them by the denominator, therefore multiply the ENTIRE equation by 2 to get get x+2y=-4

Lastly we want to actually solve for the x-intercept. The x-intercept is where the y-value is always 0 and where the line would pass through the x-axis. Because the y-value is always 0 we need to put 0 as our y-value in the equation so it looks like x+2(0)=-4 in which case 2*0=0 therefore we are left with x=-4. Because we have x as -4 then our coordinate would be (-4,0)

thank you very much

Step-by-step explanation: